After 6 years Raju’s father’s age will be twice that of the
his age and 2 years ago, his mothers age was twice that of
Raju’s age. What is the sum of Raju’s parents’ age?

• Let present agree of Raju's Father be f
  Present age of Raju be r
  & present age of Raju's Mother be m
  
  
  •• After 6 years,
  Raju's Fathers age = f+6
  & Raju's age = r+6
  
  Given,
  Raju's Father age = 2(Raju's age)
  => (f+6) = 2(r+6)
  => f = 2r + 6
  
  
  •• Two years ago,
  Raju's mothers age = m-2
  & Raju's age = r-2
  
  Given,
  Raju's Mother's age = 2×( Raju's age)
  => m-2 = 2(r-2)
  => m = 2r - 2
  
  
  
  Sum of Raju's parent' s age is
  => f+m = 2r+6+2r-2
  => f+m = 4r+4
  i. e., 4 more than 4times the Raju's present age.
  
  
  •°• Sum of Raju's parent' s age is 4 more than 4times the Raju's present age.
  
  source:brainly
• 4 years agoHelpfull: Yes(13) No(1)
• 2raju+4=raju_father+raju_mother
• 4 years agoHelpfull: Yes(0) No(0)