In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
A. 21/46
B. 25/117
C. 1/50
D. 3/25

• The correct option is A.
  as we have to choose combination of boys and girl
  so required probability given by (15C2*10C1)/25C3
  = ( (15*14)/2*10)/((25*24*23)/(3*2))
  =21/46
• 4 years agoHelpfull: Yes(8) No(0)
• 10c1*15c2/25c3. On solving this u will get A is the ans
• 4 years agoHelpfull: Yes(0) No(1)
• Let , S - sample space E - event of selecting 1 girl and 2 boys.
  
  Then, n(S) = Number ways of selecting 3 students out of 25
  
  = 25C325C3
  
  = 2300.
  
  n(E) = 10C1×15C210C1×15C2 = 1050.
  
  P(E) = n(E)/n(s) = 1050/2300 = 21/46
• 4 years agoHelpfull: Yes(0) No(0)
• 25c3 = 2300
  combination for the number 3 ways is 15*7*10 = 1050
  the probability that 3 students come is = 1050/2300 = 21/46
• 4 years agoHelpfull: Yes(0) No(0)