Two cars starts from A & B and travel towards each other at speeds of 59 kmph and 60 kmph respectively at the time of their meeting the second car has travelled 120 km more than the first. The distance between A & B in kms is? (1) 720 (2) 1230 (3) 1320 (4) 600

• The speed should be 50 kmph and 60kmph:
  
  The second train has traveled 120km more than the first train...
  Now the speed of the trains A and B are 50 and 60 kmph resp.
  
  Therefore, B travels (60-50)or 10 kmph more than A.
  
  Now 120 divided by 10 is 12.....that means both the trains
  runs for 12 hrs
  
  Now the speed of the trains A and B are 50 and 60 kmph resp.
  
  Therefore, B travels (60-50)or 10 kmph more than A.
  
  Now 120 divided by 10 is 12.....that means both the trains
  runs for 12 hrs.
  
  So, A travelled =50 * 12 =600 kms.
  &, B travelled =60 * 12 =720 kms.
  --------------------------------------
  Total distance travelled is= 600 + 720 = 1320 kms.
• 5 years agoHelpfull: Yes(7) No(1)
• Speeds are 59kmph,60kmph
  Let time=Chesi
  60x-59x=x=120
  Distance from A to B =120(60+59)=1320
• 4 years agoHelpfull: Yes(5) No(7)
• when two objects travel towards each other and distance of one object is given and to find another distance with the help of two speeds of an two objects are
  
  (s1+s2/s1-s2)*d=(50+60/10)*120=1320
  Here A's speed =50 question is wrong
• 4 years agoHelpfull: Yes(4) No(0)
• The question is wrong .the speed for the slower car should be 50 kmph.Rest is cake walk
• 5 years agoHelpfull: Yes(3) No(4)
• 1320
  in the place of A speed is 59kmph it should be a 50 kmph
• 4 years agoHelpfull: Yes(2) No(0)
• In question the speed of A is 59kmph.....by that calculation the answer is 1536kms
• 4 years agoHelpfull: Yes(1) No(0)
• 120(59+60)
  1320
• 4 years agoHelpfull: Yes(1) No(0)
• there is correction in the question speed of car A is 50 kmph .
  now using formula [ V = D/T ].
  LET they reach at a point by travelling for same time T ,
  THEN, at time "T" the car A travel (x/50)
  now car B travel in time "T" (120+x)/60.
  so equating both we get
  
  x/50 = 120+x /60 => x = 600 km
  
  so distance between A and B is ( x+ 120+x ) = 600+120+600 = 1320 km
  so distance = 1320 km
• 4 years agoHelpfull: Yes(1) No(1)
• plllz change it 50 kmph will be bro.....misprint...
• 4 years agoHelpfull: Yes(1) No(0)
• if we take speed of first car as 50kmph then,
  (120+x)/60 = x/50
  50(120) + 50x = 60x
  6000 = 60x-50x
  6000 = 10x
  x = 600 km
  hence total distance = 120 + x + x
  = 120 + 600 + 600
  = 1320 km
• 4 years agoHelpfull: Yes(0) No(0)
• 1320 Kms
  A travelled 50*12=600 Kms
  B travelled 60*12=720kms
  So the Distance travelled A and B is 600+720=1320 kms
• 3 years agoHelpfull: Yes(0) No(0)
• A speed=50kmph
  B speed=60kmph
  now If B had travelled x km then A had travelled 120+x
  so 120+x/x=60/50
  x=600 i.e B
  x+120=720 i.e A
  now A+B=600+720=1320
• 3 years agoHelpfull: Yes(0) No(0)