What is the ratio of the surface area formed by placing 3 cubes adjacently to the sum of the individual surface area of these 3 cubes?
A) 49:81 B) 27:23 C) 7:9 D) 8:9

• Volume of a cube = 6a2
  Volume of 3 cubes = 18a2
  Volume of three cubes placing adjacent each other = 6a2+5a2+5a2= 16a2
  Ratio= 16/18 = 8:9
• 4 years agoHelpfull: Yes(1) No(2)
• Ans:- C
  Let the side of a cube be 'a'
  Total surface area of a cube=6a^2
  Total surface area of a 3 cubes=3*6a^2=18a^2
  After joining 3 cubes In a row
  Length of cuboid=3a
  Breadth and height of a cuboid=a
  Total surface area of cuboid=2(3a^2+a^2+3a^2)=14a^2
  Ratio of total surface area of cuboid to the total surface area of 3 cubes=14a^2/18a^2=7/9
  Ans:-7/9
• 3 years agoHelpfull: Yes(1) No(0)