A mixture of 60 liters of salt and water contains 70%of salts. How much water must be added to decrease the salt percentage to 60%?
A)15 litres B)20 litres C)10 litres D)18 litres

• Mixture of salt & water = 60 litre
  
  Salt % = 70%
  
  70% Salt = (70/100) * 60 = 42 Litre
  
  Water = 60 - 42 = 18 Litre
  
  Let say x litre water is added
  
  then Misxture = 60 + x litre
  
  Salt = 42 Litre
  
  Salt % = 60%
  
  (42/(60+x) ) * 100 = 60
  
  => 70 = 60 + x
  
  => x = 10
  
  10 litre of water need to be added
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• 70% of 60 = 60% of x
  x = 70 litre
  ans = 70 - 60 = 10 litre add
• 3 years agoHelpfull: Yes(0) No(0)