The difference between the present age of a man and of his daughter is 30. The average of their ages after 5 years will be 21. Sum of their present ages is
1)32 2)36 3)34 4)38

• Consider present age of man and his daughter is X and Y respectively.
  
  We find answer from second line itself.
  Their ages after five year is (x+5) and (y+5)
  Average is,
  21=(x+5) + (y+5) / 2
  42=x+y+10
  X+Y=32
  Therefore sum of their present ages is 32.
• 4 years agoHelpfull: Yes(2) No(0)
• It is option a
• 4 years agoHelpfull: Yes(0) No(0)
• Average age of daughter and man after 5 years is 21.
  Then man's age=x
  Daughter's age=y
  Average age=21
  ((x+5)+(y+2))/2=21
  x+y+10=42
  x+y=42-10
  Then ,x+y=32
  Ans:option 1:32
• 3 years agoHelpfull: Yes(0) No(0)
• ans=1
  let man=m,daughter=d
  m-d=30
  after 5 years man=m+5
  daughter = d+5
  avg is,
  21=(m+5)+(d+5)/2
  21*2=m+5+d+5
  42=m+d+10
  42-10=m+d
  32=m+d
  so the sum of the present age of father and daughter is =32
• 3 years agoHelpfull: Yes(0) No(0)