A father is three times as old as his son. After twelve years father will be twice as old as the age of son at that time. Find the difference between present age of father and his son
A)18 B)27 C)24 D)30 E)None of these

• son's age=x
  father;s age=3x
  after 12 years father will be twice as old as the age of son at that time ,which means 3x+12=2(x+12)
  3x+12=2x+24
  x=12
  now,fathers age=3*12=36
  son age = 12
  diff b/w their ages is 36-12=24.
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• It is option c
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• let son age =x
  father age = 3x
  after 12 year => 3x+12=2(x+12)=> x=12
  son age = 12
  father age =36
  difference =24
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• let father is F and son is S
  F=3*S --------------(i)
  after 12 years father is F+12
  and son is S+12
  so as per question=F+12=2*(S+12)
  F+12=2S+24
  F-2S=12 -------------(ii)
  let put the value of a father in equation ii
  3S-2S=12
  S=12
  now put the value of s in equation i
  F=3*S
  F=3*12
  F=36
  so the difference between present age of father and son is =>36-12=24
  ans is C
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