Find the smallest number which leaves 13, 30, 40 and 43 as remainders when divided by 18, 35, 45 and 48 respectively.
A)67075 B)5035 C)7585 D)6245

• LCM of 13,30,40 and 43 is 67080
  
  Now,
  
  18 - 13 = 5
  
  35 - 30 = 5
  
  45 - 40 = 5
  
  48 - 43 = 5
  So, (67080- 5 = 67075) will have the remainder of 14, 19, 29, and 34 when divided by 20, 25, 35, and 40 resp.
  
  Ans: 67075
• 4 years agoHelpfull: Yes(2) No(5)
• 18 - 13 = 5
  35 - 30 = 5
  45 - 40 = 5
  48 - 43 = 5
  LCM of 18, 35, 45 and 48 is 5040.
  Therefore , 5040-5 = 5035
  ANS: 5035
• 4 years agoHelpfull: Yes(2) No(0)
• LCM of 18,35,45,48 is 5040
  remainder = 18-13=5
  35-30=5
  45-40=5
  48-43=5
  thus , smallest number = 5040-5=5035
• 4 years agoHelpfull: Yes(2) No(0)