The average of six consecutive odd numbers is 16. What is the product of the highest and lowest numbers:
(a)209 (b)247 (c)255 (d)231

• ans is 231
  Let the numbers be x, x + 2, x + 4, x + 6 and x + 8,x+10
  
  Then [x + (x + 2) + (x + 4) + (x + 6) + (x + 8+x+10) ] / 6 = 16
  after solving it we get x=11,which is lowest and highest is x+10
  11+10=21
  so,21*11=231
• 4 years agoHelpfull: Yes(1) No(0)
• let n+1 is first odd number hence average of 6 consecutive odd number will be
  (n+1+n+3+n+5+n+7+n+9+n+11)/6 = 16
  after solving the equation we get n= 10
  hence product of lowest and highest number is (n+1)*(n+11)
  i.e 11*21 = 231
• 4 years agoHelpfull: Yes(1) No(0)