Capgemini
Company
Numerical Ability
Percentage
In an examination in which full marks were 500. A got 10% less than B, B got 25% more than C and C got 20% less than D. If A got 360 marks, what percentage of full marks was obtained by D?
A)80.4% B)71.2% C)76% D)84.6%
Read Solution (Total 2)
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- ans is 71.2%
A marks=360
A got 10% less than B =(360*10)/100=36
A/c to question, B marks=360+36=396
B got 25% more than C = (396*25)/100=99
then C marks=396-99=297
20% less than D= (297*25)/100=59.4
then D marks=297+59.4=356.4
D marks in %= (356.4*100)/500= 71.2% - 4 years agoHelpfull: Yes(1) No(0)
- A got 10 per more than B
=> 360 = B - 10%B
Turning it to decimal form
=> 360 = 0.9B
=> B = 400
By doing same we find C = 320 and d = 400
Which is 80 per of 500
By doing the same - 7 Months agoHelpfull: Yes(0) No(0)
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