Hexaware Company Numerical Ability Age Problem

12 years ago the ratio between the ages of A and B was 1 : 3 respectively. The present age of B is 3⅔ times of present age of C. If C is 16 years old at present, then what is present age of A? (in years)
A)48 B)18 C)24 D)30 E)66

Read Solution (Total 1)

(A-12)/(B-12)=1/3
B=11/3 C
C=16
From this B=58.66
Submit in 1st equation will get A=17.88
Nearly equals to 18
4 years agoHelpfull: Yes(0) No(7)

Hexaware Other Question

(1/3)rd the diagonal of a square is 2. What is the measure of the side of the concerned square?
A)5√2 m B)6 m C)4 m D)3√2 m E)3 m Find missing number in the following series.
3, ?, 14, 55, 274, 1643
A)11 B)5 C)6 D)8 E)7