The perimeter of a rectangle whose length is 6m more than its breadth is 84m. What would be the area of a triangle whose base is equal to the diagonal of the rectangle and whose height is equal to the length of the rectangle? (in m²)
A)324 B)372 C)360 D)364 E)348

• perimeter =2(l+b)=84=>l+b=42
  l-b=6
  solving both,l=24,b=18
  now diagonals by pythagoras therom can be found out as
  square root of 24*24+18*18=square root of 900=30ht
  area of the triangle=1/2*b*ht=1/2*24*30=360
• 4 years agoHelpfull: Yes(3) No(0)