Hexaware
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Numerical Ability
Time and Work
A and B can do a piece of work in 8 days. B and C can do it in 12 days and A and C in 16 days. Working together they will complete the work in how many days?
A)9.48 days B)12.2 days C)14.76 days D)7.38 days
Read Solution (Total 4)
-
- A+B=8 units=48/8=6
B+C=12 units=48/12=4
A+C=16 units=48/16=3
LCM=48 total units=6+4+3=13
2A+2B+2C=13
2(A+B+C)=13
A+B+C=13/2=6.5
ans=48/6.5=7.38 days - 4 years agoHelpfull: Yes(1) No(0)
- D
Y
. - 4 years agoHelpfull: Yes(0) No(2)
- A+B=8 units=>48/8=6 (LCM of 8,12,16 is 48)
B+C=12units=>48/12=4
A+C=16units=>48/16=3
=>6+4+3=13
2A+2B+2C=13
2(A+B+C)=13
A+B+C=13/2
=>48*2/3=96/13
=>7.38 - 2 years agoHelpfull: Yes(0) No(0)
- 2(A+B+C)=13(per day)
- 1 year agoHelpfull: Yes(0) No(0)
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