Using all the letters of the word 'NOKIA' how many words can be formed, which begin with N and end with A?
A)6 B)18 C)12 D)24

• There are five letters in the given word.
  consider 5 blanks
  The first blank and last blank must be filled with N and A all the remaining three blanks can be filled with the remaining 3 letters in 3! ways=3*2*1=6
  Ans:6
• 4 years agoHelpfull: Yes(6) No(0)
• N and A fixed
  OKI - 3!=3*2*1= 6
• 4 years agoHelpfull: Yes(1) No(0)
• Nokia is a 5 letter word
  N and A are at same position they can be arranged in 2! Ways .
  And remaining 3 letters arranged in 3! Ways
  So that, solution is 2!*3!=12
• 4 years agoHelpfull: Yes(0) No(4)
• 3!=1*2*3=6
• 4 years agoHelpfull: Yes(0) No(0)
• 4*3*2*1=24
• 4 years agoHelpfull: Yes(0) No(2)
• There are five letters in the given word.
  Consider 5 blanks
  The first blank and last blank must be filled with N and A all the remaining three blanks can be filled with the remaining 3 letters in 3! ways.
  The number of words = 3! = 6.
• 4 years agoHelpfull: Yes(0) No(0)
• N and A are fixed
  So we have three letter i.e,=3!
  so 31*2!=6
• 4 years agoHelpfull: Yes(0) No(0)