A 28-litre solution contains oil and kerosene in the ratio 5:3, replace 4 liters of a mixture with 4 liters of kerosene what will be the ratio of oil and kerosene?
1)11/9 2)7/5 3)8/7 4)15/13 5)None of these

• I think answer is 15/13.
  vol of oil is 5/8*28
  vol of kerosene is 3/8*28
  then 4 liters taken off and replace with kerosene
  so vol of oil=5/8*24=15
  vol of kerosene =3/8*24+4=13
  so ratio of oil and kerosene is 15:13
• 4 years agoHelpfull: Yes(4) No(0)
• given 28-litre solution contains oil and kerosene in the ratio 5:3
  
  for one liter ( 0.625 of oil + 0.375 of kerosene )
  
  for 4 liters = 4 ( 0.625 and 0.375 ) = 2.5 oil and 1.5 kerosene
  
  now quantity of Oil = 5/8*28 = ( 0.625*28 ) = 17.5
  
  now quantity of Kerosene = 3/8*28 = ( 0.375*28 ) = 10.5
  
  now 4 liters mixture is replaced means
  
  17.5-(2.5) + 10.5 - (1.5)= 15 + 9
  
  4 literes is added to kerosene
  
  9+4= 13 liters
  
  so final quantity of oil and kerosene is 15:13
• 1 year agoHelpfull: Yes(1) No(0)
• 28-4=24 L
  oil = 5/8*24=15L
  then kerosene= 24-15 = 9 L
  
  9+4=13 L kerosene
  
  ratio = 15/13
• 3 years agoHelpfull: Yes(0) No(0)
• Fq = 28(1-x/c)^1
  Fq=28(1-4/28)^1
  Fq=24
  So the ratio is 5:3
  5/8*24=15
  3/8*24=9+4(acc to ques) so ans is 15:13
• 1 year agoHelpfull: Yes(0) No(0)