A milk vendor has two cans of milk. The first contains 30% water and the rest milk. The second contains 40% water. How much milk should he mix from each of the containers so as to get 16 litres of milk such that the ratio of water to milk is 4:5?
A)4 litres, 12 litres B)8 litres, 8 litres C)10 litres, 6 litres D)9 litres, 7 litres E)None of these

• E)None of these
  consider 1 litre milk is 1 Rs.
  so from first can 70/100 is milk which 7/10
  7/10 litre milk is 7/10 Rs
  
  second can 6/10 litre is 6/10 Rs.
  
  mixure ratio is 4:5
  milk is 5/9
  
  7/10 6/10
  5/9
  4/90 : 13/90
  
  4:13
  milk is 13/17 parts
  so (13/17)*16 litres milk
  so 12.2litres milk and 3.8litres water
• 4 years agoHelpfull: Yes(0) No(1)
• First can contains 30% of water ie 3/10
  So the milk contained is (1-3/10)=7/10
  Second can contains 40% water ie 4/10
  So milk = 6/10
  Now the milk in final litre of mix =(7/10+6/10)/2=13/20
  (13/20-7/10)=1/20 and (7/10-13/20)=1/20
  So the ratio is 1:1
  1/2*16 = 8
  So ans is 8 litres and 8 litres
• 3 years agoHelpfull: Yes(0) No(0)