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Time and Work
In the normal course, Rakesh, Sanket and Mukesh can each individually build a wall in 10,16 and 20 days respectively. Due to difficult terrain and slushy conditions at the site, the individual time required for each to complete the work has increased by 20%, 25% and 50% respectively. How long will they take to build the wall if they work together?
1)6 days 2)8 days 3)4 days 4)5½ days
Read Solution (Total 5)
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- rakesh=10days,sanket=16 days,mukesh=20 days
after increasing by 20%,25%,50%.....
rakesh=12days,sanket=20 days,mukesh=30 days
lcm=60
rate of each =5,3,2 respectively
5+3+2=10
no. of days=60/10=6 days - 4 years agoHelpfull: Yes(5) No(0)
- Answer: 6 days
let R-Rakesh, S-Sanket, M-Mukesh
R's 1 day work 1/10
S's 1 day work 1/16
M's 1 day work 1/20
Due to difficult terrain and slushy conditions time taken by them increases as
10+20%10, 16+25%16, 50+50%50 = 12, 20, 30
if they work together the total work is
1/12+1/20+1/30 = 1/6
Thus they together will complete the work in 6 days - 4 years agoHelpfull: Yes(3) No(0)
- if they work together they will complete this work in 4 12/17 days. with their efficiency 8,5,4 respectively.
due to some difficulties their working day will increase by 2 days 4 days 10 days respectively. and their efficiency will become 5,3,2 respectively. total days will take to complete this wpork will be 6 days. - 4 years agoHelpfull: Yes(0) No(0)
- TIME AND WORK :
Rakesh work in 1 day = 1/10
Sanket work in 1 day = 1/16
Mukesh work in 1 day = 1/50
After increment :
Rakesh work in 1 day =( 10+10*20/100=12 ) => 1/12
Sanket work in 1 day =( 16+16*25/100=20) => 1/20
Mukesh work in 1 day = (20+20*50/100 = 30) => 1/30
working together = 1/12+1/20+1/30 = 1/6
work will be completed in 6 days !! - 4 years agoHelpfull: Yes(0) No(0)
- rakesh=15 days
sanket=20 days
mukesh=30 days
total work is 60 (lcm of 15 , 20 , and 30)
efficiency of rakesh ,sanket and mukesh is 5 ,3,2 unit per day
so they will do 10 unit of work per day
so total work is 60
so 60/10 =6 days answer - 4 years agoHelpfull: Yes(0) No(1)
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