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The value of a car depreciates in such a way that its value of the end of each year is 4/5 of its value of the beginning of the same year. If the value at the end of 3 years is Rs. 6,40,000, then initial value of the car (Rs) is _____

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ans is RS 12,50,000
let initial value be P.
then at the end of year we have = 4/5*(P)
after 3 year we have = [4/5]^3 * P

but its value is given after 3 year we have 640000.
so
(4/5)^3 * P = 640000
P = 640000 * 5/4 * 5/4 * 5/4 = 12,50,000
3 years agoHelpfull: Yes(4) No(0)

as we know it depreciates 4/5 every year
Let total be x
1]so after 1 year it becomes 4/5x .lets take 4/5x=y
2]so after 2 year it becomes 4/5y.lets take 4/5y=z
3]so after 3 year it becomes 4/5z
now 4/5z640000
so z=800000
so obtain value of y as y=1000000
now value of x=1250000
2 years agoHelpfull: Yes(0) No(0)

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