How many words can be formed using the letters of the word DAUGHTER, so that all the vowels occurs together?
1)8640 2)2880 3)6720 4)4320

• first we arrange the constant letter and take all vowel as one letter so
  we have 5 constant and 1 another letter so arrange these 6 letter is = 6!
  now arrenge the vowel word = 3!
  
  so total words can be formed = 6! x 3! = 4320
• 3 years agoHelpfull: Yes(11) No(0)
• Total 8 letters
  Two groups (Vowels(3) and Consonants(5))
  3 vowels can be arranged among themselves in 3! ways
  Now treat the vowels as 1 group
  And we have 5 individual consonants (Total = 6)
  Hence 3! x 6! = 4320
• 3 years agoHelpfull: Yes(2) No(0)
• DAUGHTER
  VOWEL=AUE IS 1 UNIT
  CONSONANT=DGHTR 2nd UNIT
  SO 1+5=6!*3!=4320
• 3 years agoHelpfull: Yes(2) No(0)
• 6! x 3! = 4320
  option 4
• 3 years agoHelpfull: Yes(1) No(0)
• Group vowels together then taking all vowels as single letter
  6! *3! =4320
• 3 years agoHelpfull: Yes(1) No(0)
• 6!*3!=4320
• 3 years agoHelpfull: Yes(1) No(0)
• 4320 is the right answer
  explaination:- we will make all vowel into 1 unit :
  6!*3!=4320
• 3 years agoHelpfull: Yes(1) No(0)
• There are 8 letters in the word "Daughter"
  In this 3 letters are vowels..
  So the remaining letters are 5
  All the vowels occurs together ,then 3 vowels are considered as 1 letter
  So total 6 letters can be arranged as 6! Ways nd also 3 vowels can be placed 3! Ways.
  There for 6!*3!=4320
• 3 years agoHelpfull: Yes(1) No(0)
• 4) 4320
  
  DGHTR(AUE)
  6! × 3! = 4320
• 3 years agoHelpfull: Yes(1) No(0)
• 8!/3!=6720 is the answer
• 3 years agoHelpfull: Yes(0) No(11)
• Answer is 4)4320 because as vowels are together so they can be arranged in 3! ways and the other letters can be arranged in 6! ways. So resultant is 6!*3! = 4320.
• 1 year agoHelpfull: Yes(0) No(0)
• 3!*6!=4320
• 1 year agoHelpfull: Yes(0) No(0)