CAT
Exam
Numerical Ability
Number System
The remainder, when (15^23+23^23) is divided by 19, is
A)4
B)15
C)0
D)18
Read Solution (Total 2)
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- A^n + B^n is always divisible by a+b if n is odd so this expression will be divisible by 38 and hence by 19 as well. Hence remainder is 0
c)0 - 3 years agoHelpfull: Yes(1) No(0)
- 0 breaking n binomial expression as (19-4)^23+(19+4)^23
- 15 Days agoHelpfull: Yes(0) No(0)
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