The ratio in which tea costing Rs. 192 per kg is to be mixed with tea costing Rs. 150 per kg, so that the mixed tea when sold for Rs. 194.4 per kg, gives a profit of 20%
A)5:3 B)5:2 C)2:5 D)3:5

• Let the CP of the mixture be x
  As the mixture is sold at a profit of 20%, the SP would be x + 0.2x
  Given, the SP of mixture is 194.4
  Hence, x=0.2x = 194.4
  On solving, we get x = 162
  Now we can apply allegation formula
  192 150
  /
  162
  /
  162-150 192-162
  
  Hence, the ratio we get is 12 : 30 or 2 : 5
• 3 years agoHelpfull: Yes(12) No(2)
• CP of first tea = Rs. 192 per kg.
  CP of Second tea = Rs. 150 per kg.
  Mixture is to be sold in Rs. 194.40 per kg, which has included 20% profit. So,
  SP of Mixture = Rs. 194.40 per kg.
  Let the CP of Mixture be Rs. X per kg. Therefore,
  X + 20% of X = SP
  6X5
  = 194.40
  6X = 194.40 *5
  X = Rs. 162 per kg.
  Let N kg of first tea and M kg of second tea to be added.
  Now, Using Alligation,
  We get,
  Alligation mcq Solution1
  NM=1230
  
  N : M = 2 : 5
• 3 years agoHelpfull: Yes(6) No(2)
• 20% profit means 1.2*x=194.4
  x=162;
  150 192
  162
  (192-162) (162-150)
  30 12
  5:2
• 3 years agoHelpfull: Yes(5) No(2)
• S.P = 194.4
  C.P= X
  now S.P = C.P+ 20% of C.P
  => 194.4 = X+20% of X
  => 194.4 = X+1/5 of X (as 20% = 1/5)
  => 194.4 = 6X /5 => 194.4 x 5 / 6 = 162
  now 194 150
  /
  162
  /
  ( 162-150) (192-162)
  12 : 30
  = 2 : 5
• 3 years agoHelpfull: Yes(1) No(0)
• 100/120=x/194.4 x->162
  (192-162)/(162-150)=30/12=5/2
  5:2
• 3 years agoHelpfull: Yes(0) No(0)
• C.P of first tea = Rs. 192 per kg
  C.P of second tea = Rs. 150 per kg
  S.P of the mixture = Rs. 194.40 per kg.
  Profit =20%
  Let C.P of the mixture be Rs. x per kg
  ⇒x+20% of x =194.40
  6x /5 = 194.40
  6x = 194.40* 5
  X = 972/ 6
  X = rs. 162 per kg.
  Let N be the first kg of tea and M be the second kg of tea .
  Thus alligation, we have
  First tea = 162 - 150 = 12.
  Second tea = 192 - 162 = 30
  M/N = 12 / 30
  N / M = 2/ 5.
  N:M = 2: 5.
• 1 year agoHelpfull: Yes(0) No(0)