Exam
Maths Puzzle
Numerical Ability
LCM and HCF
find the least number which is exactly divisible by 11/6,8/6,7/2 and 11/2
Read Solution (Total 1)
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- L.C.M = LCM of the Numerators / HCF of the Denominators = LCM (11, 8, 7) / HCF (6, 2) = 616/2 = 308
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