The diameter of a circle A is (a+b) units. Find the radius of a semi-circle whose area is 300%more than that of circle A.

• Given, diameter of a circle A=(a+b), so Radius=(a+b)/2 and Area=Pi*[(a+b)/2]^2
  .'. Area of a semi-circle=Pi*[(a+b)/2]^2 + (300/100)*Pi*[(a+b)/2]^2=4*Pi*[(a+b)/2]^2
  Let Radius of semi-circle=R, then Area of Semi-circle=Pi*R^2=4*Pi*[(a+b)/2]^2
  => R^2=4*[(a+b)/2]^2
  R=(a+b)
  Hence radius of a semi-circle=(a+b)
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