if 0 is the center of a circle of radius r,Ac and BC are chords of lengths(r-2) and (r+16) respectively then what oculd be the radius of the circle

• In
  Δ
  A
  O
  P
  , by Pythagoras theorem
  
  r
  2
  =
  3
  2
  +
  (
  1
  +
  x
  )
  2
  ....(1)
  
  In
  Δ
  C
  O
  Q
  ,
  r
  2
  =
  4
  2
  +
  x
  2
  ...(2)
  
  e
  q
  n
  (
  1
  )
  −
  e
  q
  n
  (
  2
  )
  O
  =
  9
  −
  16
  +
  (
  1
  +
  x
  )
  2
  −
  x
  2
  
  ⇒
  2
  x
  =
  6
  →
  x
  =
  3
  
  By, eqn (1)
  r
  2
  =
  9
  +
  16
  ⇒
  r
  2
  =
  25
  ⇒
  r
  =
  5
  c
  m
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