MBA
Exam
Numerical Ability
Number System
Find the number of divisors of 1080 excluding the throughout divisors, which are perfect squares?please post the answer anon.. 1) 29 2) 28 3) 30 4) 31
Read Solution (Total 3)
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- 1080= 2^3 *3^3 *5
total divisors = 4*4*2= 32
square divisors = (2^0,2^2) (3^0,3^2) (5^0) [note: only these factors give rise to square factors] so 2*2*1=4;
non square divisors=total divisors-square divisors
32-4=28.
- 11 years agoHelpfull: Yes(0) No(1)
- 1080= 2^3 *3^3 *5
total divisors = 4*4*2= 32
square divisors = (2^0,2^2) (3^0,3^2) (5^0) [note: only these factors give rise to square factors] so 2*2*1=4;
non square divisors=total divisors-square divisors
32-4=28.
- 11 years agoHelpfull: Yes(0) No(1)
- Can you guys please explain ...how you calculated total divisors???
i.e from where does this 4*4*2 came from???
please explain - 8 years agoHelpfull: Yes(0) No(0)
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