The lowest temperature in the night in a city A is 1/3 more than 1/2 the highest during the day. Sum of the lowest temperature and the highest temperature is 100 degrees. Then what is the low temp?

• Let the high temp be x.
  
  Low temp therefore is (1/2)x + (1/3)*(1/2)x, or simply (4/3)*(1/2)x, which is (4/6)x, or (2/3)x.
  
  The sum is 100...
  
  (2/3)x + x = 100
  
  (5/3)x = 100
  
  x = 60.
  
  So the low temp is 40.
• 13 years agoHelpfull: Yes(9) No(20)
• x=54.54
  y=45
  
• 9 years agoHelpfull: Yes(1) No(1)
• Let the lowest temp be l and highest temp be h
  l=1/3 +1/2h
  l+h=100
  Solving both the above eqs, l= 33.5deg
• 9 years agoHelpfull: Yes(1) No(1)
• Let the high temp be x.
  Then the Low temp is given as (1/2)x + (1/3)*(1/2)x
  thus the low temp is 2/3x
  If the sum is 100
  Then (2/3)x + x = 100
  (5/3)x = 100
  x = 60
  Since Low temp is 2/3x , the value is 20
• 9 years agoHelpfull: Yes(0) No(1)