Q Consider trianglePQR such that PQ = 4, PR = 5 and QR = 6. Similarly, we have a point S such that QS = 5, RS = 4, and PQSR is a parallelogram. The angle bisector of angle P intersects QS at T, and the angle bisector of angle PQT intersects PT at U. Then the length of TU is

1) 3
2) (4√6) /3
3) 2
4) 9/2