MBA
Exam
how many positive integers "n" can we form from the digits 3,4,4,5,6,6,7 if we want "n" to exceed 6,000,000? (IIFT 2010)plz post d approach 1) 320 2) 360 3) 540 4) 720
Read Solution (Total 1)
-
- when first digit is 6 , number of integers = 6!/2! = 360
first digit is 7 , number of integers = 6!/2!2! =180
total 360+180=540 integers - 11 years agoHelpfull: Yes(0) No(0)
MBA Other Question