MBA
Exam
how many positive integers "n" can we form from the digits 3,4,4,5,6,6,7 if we want "n" to exceed 6,000,000? (IIFT 2010)plz post d approach
1) 320
2) 360
3) 540
4) 720
Read Solution (Total 1)
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- when first digit is 6 , number of integers = 6!/2! = 360
first digit is 7 , number of integers = 6!/2!2! =180
total 360+180=540 integers - 12 years agoHelpfull: Yes(0) No(0)
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