the breadth of a rectangle decreases by 10% and then increases by 40%. by what percent should the length decrease so that the area remains the same?pl. provide sol also.

1) 23 1/13%
2) 23 28/3%
3) 24 1/13%
4) 20 40/63%

• 20 40/63%
  
  
  If length of rectangle should decrease by x% for keeping area same, then
  l*b = (l*(100-x)/100 )*b*0.9*1.4
  solving it,
  x= 20 40/63%
• 11 years agoHelpfull: Yes(0) No(0)
• solution is 4) 20 40/63%
  let x be breadth and y be length
  value of x after dec. and inc. =x*(90/100)*(140/100)
  =x*126/100
  now area =y*x*126/100 that sud be equal to x*y
  so y is decreased by 100/126
  so change in y=y-y*100/126=1y*26/126
  % change=(26/126)*100
  20 40/63%
• 11 years agoHelpfull: Yes(0) No(0)