A person with some money spends 1/3 for cloths, 1/5 of the remaining for food and 1/4 of the remaining for travel. He is left with Rs 100/-. How much did he have with him in the beginning?

• Ans:250
  Let intial amt be x
  He spents 1/3 for cloths =x/3 and remaining amt be 2x/3
  He spents 1/5 of remaining for food =(2x/3)/5 = 2x/15 and remaining amt be 8x/15
  He spents 1/4 of remaining for cloths =(8x/15)/4= 2x/15 and remaining amt be 6x/15
  Given remaining amt at last 6x/15 =100
  x=250
• 13 years agoHelpfull: Yes(25) No(0)
• Ans is Rs.250/-
  
  let the money he have with him in the beginning be x
  theerfore, (x/3)+(y/5)+(z/4)+100=x
  here y=2x/3
  z=4y/5=8x/15
  hence (x/3)+(2x/15)+(8x/60)+100=x
  x-(36x/60)=100
  x=250
  the amount of money he had with him in the beginning is Rs.250/-
• 13 years agoHelpfull: Yes(9) No(1)
• the answer is 250 right approach
  the other way is 2 sum all the expanses and then add them and subtract from initial ........ but it is the easy approach
• 12 years agoHelpfull: Yes(3) No(2)
• 250
• 13 years agoHelpfull: Yes(1) No(2)
• 250 rupees.............
  suppose initially x rupees are there....... so
  x-(x/3+((2x/3)/5)+((8x)/4))=100....from this x=250...
• 13 years agoHelpfull: Yes(1) No(0)
• x/3+x/5+x/4+100=x
  yhen x=461.53846
• 12 years agoHelpfull: Yes(1) No(12)