MBA
Exam
1,3,3,3,5,5,5,5,5,7,7,7,7,7,7,7 and so on-What is the 111th term of the series .Please post approach also.. 1) 19 2) 21 3) 111 4) None
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- 21 is 111 th term in series.
1+3+5+7+......n terms = 111
n/2(2+(n-1)*2)=111
n^2=111
so n will lie between 10 and 11 in normal AP.
so from 100th to 121 th terms will be 1+2*10=21 - 11 years agoHelpfull: Yes(1) No(0)
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