MBA Exam

1,3,3,3,5,5,5,5,5,7,7,7,7,7,7,7 and so on-What is the 111th term of the series .Please post approach also..

1) 19
2) 21
3) 111
4) None

Read Solution (Total 1)

21 is 111 th term in series.

1+3+5+7+......n terms = 111
n/2(2+(n-1)*2)=111
n^2=111
so n will lie between 10 and 11 in normal AP.
so from 100th to 121 th terms will be 1+2*10=21
12 years agoHelpfull: Yes(1) No(0)

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