Rs. 69 were divided among 115 students so that each girl gets 50 paise less than a boy. Thus each boy received twice the paise as each girl received. The no. of girls in the class is? (Post the approach also)

1) 92
2) 42
3) 23
4) 46

• Let X be the no. of Girls and Y be the no. of Boys.
  Let a be the amount Girls receive and b be the amount Boys receive.
  So the equations 1 & 2 are
  X + Y = 115
  aX + bY = 69
  Also, a = b - 0.5
  and b = 2a
  so a = Rs. 0.5 and b = Re. 1
  Putting values of a and b in Equation 2 and solving 1 and 2
  We get, X = 92 and Y = 23
  Thus, no. of Girls (X) in the class is 92.
• 8 years agoHelpfull: Yes(5) No(2)
• let the no of boys be x,then no of girls is (115-x)
  each boys received twice the paisa as received by each girls.
  if total paisa received by (115-x) girls is 50(115-x),then total paisa received x boys must be 100x.
  thus,
  100x+50(115-x)=6900; (since rs 69= 6900p)
  this gives x=23 which is no of boys and hence no of girls =115-23=92(answer)
  
• 8 years agoHelpfull: Yes(1) No(0)
• let boy get x paise girls (x-50)paise
  given x=2(x-50) x=100paise
  from option 92 is answer
• 10 years agoHelpfull: Yes(0) No(2)
• 2+1=3 is for 2 student(1 boy and 1 girl)
  1.5 paise for 2 student(1 boy and 1 girl)
  therefor
  69/1.5*2=92
• 8 years agoHelpfull: Yes(0) No(0)