remainder when 888222888222888222...........upto 9235 digit is divided by 5^3 ??????????? ans. this with approach

1) 103
2) 38
3) can't be determine
4) none of this

• 1) 103
  
  First 3 digits, 888 divided by 125 => remainder = 13
  Next 3 digits , 13222 => remainder = 97
  Next 3 digits , 97888 => remainder = 13
  
  This repetition continues i.e. after 222, remainder is 97
  
  9235 digits => last four digits = 2228
  => remainder = 978 divided by 125 = 103
  
• 11 years agoHelpfull: Yes(0) No(0)