The diluted wine contains only 8L of wine and the rest is water. A new mixture whose concentration is 30% is to be formed by replacing wine. How many Liters of mixture shall be replaced with pure wine if there was initially 32L of water in mixture?(Post approach also)

1) 5
2) 4
3) 6
4) 2

• wine water
  8 32
  1 : 4
  20% 80%.....original
  30% 70%..........require
  
  7/8 = 1-x/40
  8 = 320-280
  40/8 = 5 litres
• 7 years agoHelpfull: Yes(0) No(2)