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Numerical Ability
Permutation and Combination
There is 7 friends (A1, A2, A3....A7).If A1 have to have shake with all without repeat. How many handshakes possible?
a) 6 b) 21 c) 28 d) 7
Read Solution (Total 4)
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- a1 with (a2, a3,a4,a5,a6,a7)
6 handshakes - 13 years agoHelpfull: Yes(35) No(9)
- 21
6+5+4+3+2+1=21 - 13 years agoHelpfull: Yes(12) No(54)
- simple a1 handshakes with a1,a2,a3,a4,a5,a6
so the answer is total handshakes=6. - 12 years agoHelpfull: Yes(2) No(3)
- as handshake of a1 is asked....they handshake with (a2,a3.....a7) . so their is ( n-1) handshake so answer is 6.
- 4 years agoHelpfull: Yes(0) No(0)
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