In how many ways can 600 be expressed as a sum of two or more consecutive natural numbers??(Need a simple approach to solve this)

1) 14
2) 7
3) 6
4) 5

• 4)5
  
  By the preceding discussion, this is equal to the number of odd divisors of 600, minus one (to eliminate the trivial solution with one term.) The prime factorization of 600 is
  600=2^3 3^1 5^2
  and the number of odd divisors of 600 is (1+1)*(1+2) = 6. Therefore, there are 5 ways to write 600 as the sum of two or more consecutive positive integers.
• 8 years agoHelpfull: Yes(0) No(0)