MBA
Exam
the set S contains two digit natural no. N such that (N^3+5N^2+6N) is divisible by 8. how many elements does S contains?? 1) 44 2) 50 3) 56 4) not
Read Solution (Total 1)
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- 3) 56
(N^3+5N^2+6N)= N (N + 2) (N + 3)
From 8 to 16 , possible 2 digit numbers are 10 , 12 , 13 , 14 ,16
=> Possible 2 digit numbers are
10 , (10 + 8) , (10 + 8 + 8) ...
12 , (12 + 8) , (12 + 8 + 8) ...
13 , (13 + 8) , (13 + 8 + 8) ...
14 , (14 + 8) , (14 + 8 + 8) ...
16 , (16 + 8) , (16 + 8 + 8) ...
=> 12 + 11 + 11 + 11 + 11 = 56 numbers - 11 years agoHelpfull: Yes(0) No(0)
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