TCS
Company
Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is
a) 1 b) 3 c) 4 d) 0
Read Solution (Total 2)
-
- 1
That pt will be incentre of triangle. - 13 years agoHelpfull: Yes(1) No(9)
- its 4 if say that line segment then 1
- 13 years agoHelpfull: Yes(0) No(1)
TCS Other Question