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Maths Puzzle
There is a safe with a 5 digit number as the key. The 4th digit is 4 greater than the second digit, while the 3rd digit is 3 less than the 2nd digit. The 1st digit is thrice the last digit. There are 3 pairs whose sum is 11.
Find the number.
Read Solution (Total 5)
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- according to the given conditions, there are only 3 conditions for 2nd, 3rd and 4th digits. They are (3, 0, 7) or (4, 1, 8) or (5, 2, 9)
given,there are 3 pairs whose sum is 11.
possible pairs are (2, 9), (3, 8), (4, 7), (5, 6).
since it contains 3 pairs of 11,it must not be having 0 and 1 in it.
Hence, the only possible combination for 2nd, 3rd and 4th digits is (5, 2, 9)
Also, 1st digit is thrice the last digit.
The possible combinations are (3, 1), (6, 2) and (9, 3), out of which
only (6, 2) with (5, 2, 9) gives 3 pairs of 11. Hence, the
answer is 65292.
- 14 years agoHelpfull: Yes(14) No(0)
- Ans: 65292
Let 5 digit no be abcde
From the given ,d=b+4 ,c=b-3,a=3e
since b can't take the values 0,1,2(as c value becomes -3,-2,-1) and can take 3,4,5 as (d value becomes 7,8,9)
From the above condn , we can form 3 combination of (b,c,d) i.e (3,0,7) ,(4,1,8),(5,1,9)
Given there are 3 pairs whose sum is 11 . All possible pairs are (2, 9), (3, 8), (4, 7), (5, 6). Now required number is 5 digit number and it contains 3 pairs of 11. So it must not be having 0 and 1 in it. Hence, the only possible combination for 2nd, 3rd and 4th digits is (5, 2, 9) .
Also, 1st digit is thrice the last digit. T - 14 years agoHelpfull: Yes(10) No(0)
- 65292
- 14 years agoHelpfull: Yes(2) No(1)
- let the number be abcde---
as given--> d=b+4 , c=b-3 , a= 3e
so as we see value of b not be- 0,1,2,3,6,7,8,9 (as c should be +ve and d should
be 1 digit number)
so as we see value of e can be- 0,1,2,3 (As a should be 1 digit number)
so option we have for bcd are - 418 ,529
as it given there are three pair whose sum =11
so e should be 2 and bcd should be =529
so the number is 65292
- 13 years agoHelpfull: Yes(2) No(0)
- 29256
- 14 years agoHelpfull: Yes(0) No(5)
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