MBA Exam

You have enough coins of 1, 5, 10, 25 paise. How many combinations are possible to make 50 paise?

1) 52
2) 49
3) 44
4) 45

Read Solution (Total 1)

In that case it is easier to observe that number of 1 paisa coins must be multiple of 5. So let number of 1 paisa coins be 5a, 5paise be b, 10 paise be c and 25 paise be d.

Thus we have, 5a + 5b + 10c + 25d = 50
i.e. a + b + 2c + 5d = 10

It's easier to calculate now with smaller values. Just check by putting d = 0, 1 and 2 and the total cases come out to be: (1 + 3 + 5 + 7 + 9 + 11) + (2 + 4 + 6) + (1) = 49
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MBA Other Question

A circle of radius x cm is inscribed in an equilateral triangle and is tangent at three points. Three smaller circles are inscribed so that they are each tangent to two sides of the triangle and to the larger circle. The process is continued with circles of ever decreasing diameters. What is the sum of the areas of all the circles so drawn??

1) (3pi x^2)/ 2
2) (3pi x^2)
3) (5pi x^2)/ 2
4) (2pi x^2)
Number of ways to distribute 5 Different balls into 3 identical boxes is?

1) 40
2) 41
3) 51
4) 56