MBA
Exam
Let x denote the greatest 4-digit number which when divided by 6, 7, 8, 9 and 10 leaves a remainder of 4, 5, 6, 7 and 8 respectively. Then, the sum of the four digits of x is:(Easy) 1) 21 2) 18 3) 22 4) 25 5) None of these
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- the number will be a multiple of 6,7,8,9,10
L.C.M OF 6,7,8,9,10=2520
Largest 4 digit number divided by this = 7560
So, required no. = 7558
and therefore sum of digits = 25 :-) - 8 years agoHelpfull: Yes(1) No(0)
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