MBA Exam

How many of the following numbers can be expressed as a product of 4 natural numbers in arithmetic progression, of which exactly 3 are in geometric progression? The numbers are 384, 1944, 945, 15000.

1) 3
2) 2
3) 1
4) 4

Read Solution (Total 1)

384 = 4*16*2*3 = 2*4*8*6 (first 3 GP )
1944 = 8*27*3*3 = 3*6*12*9 (first 3 GP )
945 =5*7*27 = 3*5*7*9 (no GP)
15000 = 3*5*5*5*5*8 = 5*10*20*15 (first 3 GP )
so overall three numbers follow the given condition.
5 years agoHelpfull: Yes(0) No(0)

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