A pizza shop, there were 2 kinds of pizzas available. But now they have introduces 8 new types, a person buy two different type pizzas of new type in how many ways he can select?
(a) 24 (b) 43 (c) 56 (d) 58

• 8 new types, a person buy two different type pizzas of new type:
  By Probablity 8C2= (8*7)/(2*1)=28
• 13 years agoHelpfull: Yes(18) No(4)
• here no of selections is 8c2*2c1=28*2=56 because 8 pizzas can arrange in 8c2 ways also 2 pizzas can arrange in 2c1 ways so total arrangement is 8c2 * 2c1=56.
• 13 years agoHelpfull: Yes(12) No(11)
• its 8c2..ans is 28
• 13 years agoHelpfull: Yes(8) No(2)
• 8*7=56/2=24
• 13 years agoHelpfull: Yes(2) No(18)
• the answer according to me is 8*7=56 as this is the problem of chances.
• 13 years agoHelpfull: Yes(2) No(9)