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Numerical Ability
Time and Work
A man, a woman, and a child can do a piece of work in 6 days. Man only can do it in 24 days. Woman can do it in 16 days and in how many days child can do the same work?
(a) 8 (b) 14 (c) 16 (d) 18
Read Solution (Total 11)
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- a man ,a woman a child do 6 days 1 work 1 day 1/6 part
man can do 1 day 1/24 woman can do 1/16 so child can do 1 day (1/6-1/24-1/16)=1/16 so child can do 16 days - 13 years agoHelpfull: Yes(26) No(0)
- 16 days
1/(1/6 -1/24 - 1/16) = 48/3=16 - 13 years agoHelpfull: Yes(16) No(0)
- 1/6-1/24-1/16=1/16
Ans=1/16 - 13 years agoHelpfull: Yes(5) No(0)
- 1/6-1/24-1/16=1/16
Ans=1/16 - 13 years agoHelpfull: Yes(5) No(0)
- 1/6-1/24-1/16=1/16
Ans=1/16 - 13 years agoHelpfull: Yes(3) No(0)
- 1/6-1/24-1/16=1/16
Ans=1/16 - 13 years agoHelpfull: Yes(3) No(0)
- m+w+c=6days,
m=24days
w=16days
then total work will be lcm of these days(according to work and time law)
so lcm=48(network)
M+w+c=8unit/day,
m=2unit/day
w=3unit/day
so c=8-2-3=3unit/day
so child can complte work =48/3=16days - 7 years agoHelpfull: Yes(3) No(0)
- let assume a piece of work as 1.
GIVEN:
1/M + 1/W + 1/C =1/6
1/M=1/24
1/W=1/16
Therefore : 1/24 + 1/16 + 1/c = 1/6
the ans is 1/c = 1/16. - 5 years agoHelpfull: Yes(1) No(0)
- 1/6-1/24-1/16=1/16. so 16 will be ans.
- 9 years agoHelpfull: Yes(0) No(0)
- man+women+child=6 days,then work=1/6
man=24 days,then work=1/24
women=16 days,then work=1/16
man+women+child=total
(1/6-1/24-1/16)=1/16.
child can do work in 16 days - 9 years agoHelpfull: Yes(0) No(0)
- A+B+C=1/16
A=1/24
B=1/16
SUBSTITUTE IN ABOVE
1/24+1/16+C=1/6
C=(8-2-3)/48
=3/48
=1/16
=16DAYS
- 9 years agoHelpfull: Yes(0) No(0)
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