8 chairs are numbered from 1 to 8. Two women first choose two chairs from those marked 1 to 4 and 3 men selects 3 chairs from the remaining. Find the number of possible arrangements

• 1,2,3,4,5,6,7,8 are 8 chairs.
  two women first choose two chairs from 1,2,3,4
  in 4p2 ways = 12 different ways
  3 men selects 3 chairs from the rest 6 chairs = 6p3 = 6*5*4 = 120.
  
  Total number of possible arrangement = 12*120 = 1440.
• 11 years agoHelpfull: Yes(57) No(4)
• shouldn't it be permutation because order matters?? shouldn't it be 4P2 * 6P3 ??
• 11 years agoHelpfull: Yes(10) No(3)
• 4c2*6c3=120
• 11 years agoHelpfull: Yes(9) No(10)
• two women first choose chair in 2! way
  and now 6 seats are empty so 6 man can choose in 6! way
  2!*6!=1440
• 11 years agoHelpfull: Yes(6) No(1)
• ans is 5/28
  (4c2+4c3)/8c5
• 11 years agoHelpfull: Yes(4) No(11)
• from 8 chairs
  two women choose 2 chairs from 4 in 4P2 ways
  reamining 6, 3 men selects 3 chairs in 6p3 ways
  
  total arrangements=12*120=1440
• 11 years agoHelpfull: Yes(2) No(1)
• 4C2*4C3=24
• 6 years agoHelpfull: Yes(1) No(1)
• 1,2,3,4,5,6,7,8 are 8 chairs.
  two women first choose two chairs from 1,2,3,4
  in 4p2 ways = 12 different ways
  3 men selects 3 chairs from the rest 6 chairs = 6p3 = 6*5*4 = 120.
  
  Total number of possible arrangement = 12*120 = 1440.
• 8 years agoHelpfull: Yes(0) No(0)