IBM
Company
Numerical Ability
Algebra
A set of 7 pens, 9 erasers and 11 sharpeners costs Rs 79 and 2 pens, 5 erasers and 8 sharpeners cost Rs 42. Find the total cost of one sharpeners, one eraser and one pen.
Read Solution (Total 3)
-
- 7P+9E+11s=79 ---1
2P+5E+8S=42---2
eliminating P.... eq1 *2 - eq2*7 , gives
17E+34S=136 ----3
eliminaing S ....eq1*8-eq2*11, gives
34P+17E=170 ----4
adding eq3 and eq4,
34P+34E+34S=306
P+E+S=9 - 11 years agoHelpfull: Yes(61) No(4)
- 7p - 2p=5 p
9e - 5e=4 e
11s - 8s=3s
total cost=37
5p*4=20 total cost=20+8+9=37
4e*2=8 1pen+1e+1s=4+2+3
3s*3=9
ANS=9 - 7 years agoHelpfull: Yes(4) No(6)
- answer is 9
- 11 years agoHelpfull: Yes(2) No(11)
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