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The average price of 14 different dolls is Rs 18 while the average price of 20 of these dolls is Rs 18.20. Of the remaining two dolls if the price of one is 50% more than the price of the other. What is the price of these two dolls?
Read Solution (Total 5)
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- Ans- 44.8 & 67.2
18 dolls price= 18*14=252
20 dolls price = 20*18.20 = 364
remaining (20-18)=2 dolls price = (364-252)=112
let price of 1 doll be 'X'
price of 2nd doll will be 50% of X + X
so total price of the dolls -
X + X/2 + X = 112
ans X=44.8 & price of 2nd doll 44.8/2 + 44.8=67.2
which satisfies d problem 44.8+67.2= 112 - 10 years agoHelpfull: Yes(15) No(3)
- Ans. 74.66 and 37.33
18 dolls price = 18*14 = 252
20 dolls price = 20*18.20 = 364
remaining (20-18)=2 dolls price = (364-252)=112
now, let price of one doll is x and according question 2nd doll price will be x/2.
so, x+x/2=112
solving this x=74.66
so one doll price is Rs.74.66 and another is 37.33
- 11 years agoHelpfull: Yes(6) No(10)
- There is mistake in question itself
- 10 years agoHelpfull: Yes(6) No(0)
- bhak................
- 10 years agoHelpfull: Yes(4) No(0)
- 14*18=252
20*18.20=364
let,x and 3x/2
2 dolls=364-252=112
5x/2=112
so,x=44.8 and 3x/2=3*44.8/2=67.2 - 10 years agoHelpfull: Yes(1) No(1)
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