IBM
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Logical Reasoning
Number Series
2,3,10,15,26,?
Read Solution (Total 8)
-
- Ans= 35
(1^2)+1=2
(2^2)-1=3
(3^2)+1=10
(4^2)-1=15
(5^2)+1=26
(6^2)-1=35 - 12 years agoHelpfull: Yes(72) No(1)
- Ans is 35.
2,3,10,15,26,35
take difference of two consecutive no.=1,7,5,11,9
again take difference like +6,-2,+6,-2. - 12 years agoHelpfull: Yes(19) No(3)
- Ans is 35.
1^1+1=2
2^2-1=3
3^3+1=10
4^4-1=15
5^5+1=26
6^6-1=35 - 12 years agoHelpfull: Yes(10) No(2)
- Ans= 35
(1^2)+1=2
(2^2)-1=3
(3^2)+1=10
(4^2)-1=15
(5^2)+1=26
(6^2)-1=35 - 8 years agoHelpfull: Yes(2) No(0)
- 2*1=2
3*1=3
5*2=10
5*3=15
13*2=26
13*3=39 - 8 years agoHelpfull: Yes(1) No(2)
- ans =35 take alternate series(3,15,x)
3=1*3
15=3*5
x=5*7
x=35 ans - 8 years agoHelpfull: Yes(0) No(0)
- ANs= 35
prime number series
2
3
5*2=10+0^2
7*2=14+1^2
11*2=22+2^2
13*2=26+3^2 - 7 years agoHelpfull: Yes(0) No(0)
- ans =39
2+3=5
5*2=10
then 5(2+3)+10=15; then 3+10=13 ; so 13*2==26; after that add 13+26=39 according to the previous process. - 6 years agoHelpfull: Yes(0) No(1)
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