1)2,1,2,3,8,0,1,9,1,2,1,?
2)2,1,2,3,2,9,9,0,1,1,9,?

• for 1st series
  1st and 3rd term add then subtract 2nd term = 4th term like that
  2+2=4,4-1=3
  8+1=9,9-0=9
  1+1=2,2-2=0
  so,my ans is 0
  
• 11 years agoHelpfull: Yes(40) No(7)
• 2^1=2
  3^2=9
  9^0=1
  1^9=1....so ans is 1
• 11 years agoHelpfull: Yes(33) No(9)
• for frst one ans is 4
  3+2-(2+1)=2
  9+1-(8+0)=2
  1+4-(2+1)=2....hence ans is 4
• 11 years agoHelpfull: Yes(22) No(6)
• (2,1)==>2^1=2,
  (2,3)==>2^3=8,
  (8,0)==>8^0=1,
  (1,9)==>1^9=1,
  (1,2)==>1^2=1,
  (1,1)==>1^1=1....hence ans is 1
  
• 11 years agoHelpfull: Yes(8) No(8)
• 2^1=2
  3^2=9
  9^0=1
  1^9=1
  so ans is 1
• 11 years agoHelpfull: Yes(7) No(3)
• 2nd question: 2,1,2,3,2,9,9,0,1,1,9,?
  Take 3-3 pair:(2,1,2)(3,2,9)(9,0,1)(1,9,?)
  2^1=2
  3^2=9
  9^0=1
  1^9=9.
  Therefore answer is : 1
• 8 years agoHelpfull: Yes(7) No(0)
• 1) is d ans is 2??
• 11 years agoHelpfull: Yes(3) No(3)
• may be:
  (2+1+2+3-8 =0), (1+9+1+2+1-x =0) hence x=14
• 11 years agoHelpfull: Yes(3) No(7)
• for 2nd ans is
  2^1=2
  3^2=9
  9^0=1
  1^9=9...so the ans is 9
  
• 11 years agoHelpfull: Yes(2) No(20)
• for first series
  take four terms at a time,add 1st and 3rd terms and subtract the fourth term from this sum
  2+2=4,4-3=1
  8+1=9,9-9=0
  1+1=2,2-0=2
  so ans is 0
  
• 11 years agoHelpfull: Yes(1) No(2)
• for the 2nd series.
  
  take 3-3 pair i.e (2,1,2) (3,2,9) (9,0,1) (1,9,?)
  
  from 1st pair 2^1=2
  from 2nd pair 3^2=9
  from 3rd pair 9^0=1
  from 4th pair 1^9=9
  so the ans is 9 :)
  
• 9 years agoHelpfull: Yes(1) No(10)
• @madhurima : explain plz
• 11 years agoHelpfull: Yes(0) No(0)
• take the series like this 3,...9,...?
  3,3^2 next 3^3 or 9^2
  ans 27 or 81 may be
• 11 years agoHelpfull: Yes(0) No(6)
• is d ans 13?
  
• 11 years agoHelpfull: Yes(0) No(0)
• 1st answer is 2
  take pair of three with the first item is the last item of previous taken. and. square with 2nd term to 1st term
• 8 years agoHelpfull: Yes(0) No(0)