The bacteria have the probability of split into 3 and probability to die is 1/3rd of the total bacteria. Let the probability is P. Some of them survived with probability 1/5.Then which among the following relation is true?
a)P=1/3+1/5*3 b)P=1/5*(1/8-3)

• The bacteria have the probability of split into 3 and probability to die is 1/3rd of the total bacteria. Let the probability is P. Some of them survived with probability 1/5.Then which among the following relation is true?
  a)P=1/3+1/5*3 b)P=1/5*(1/8-3)
  
  P=1/3+1/5*3 is true.
• 13 years agoHelpfull: Yes(21) No(8)